liblexical-underscore-perl 0.004-3 source package in Ubuntu

Changelog

liblexical-underscore-perl (0.004-3) unstable; urgency=medium

  * Team upload.
  * Remove Makefile.old via debian/clean. (Closes: #1046691)

 -- gregor herrmann <email address hidden>  Wed, 06 Mar 2024 16:10:23 +0100

Upload details

Uploaded by:
Debian Perl Group
Uploaded to:
Sid
Original maintainer:
Debian Perl Group
Architectures:
all
Section:
misc
Urgency:
Medium Urgency

See full publishing history Publishing

Series Pocket Published Component Section
Oracular release universe misc

Builds

Oracular: [FULLYBUILT] amd64

Downloads

File Size SHA-256 Checksum
liblexical-underscore-perl_0.004-3.dsc 2.4 KiB be87710974ecd4671f6ccca802c39b25252bd432a1dcf65467ad6df0c86a59d1
liblexical-underscore-perl_0.004.orig.tar.gz 14.2 KiB 6bd5d1469e161e199a9bd7fdde957e04176c5707cb059597a23ca3e130fb1134
liblexical-underscore-perl_0.004-3.debian.tar.xz 4.7 KiB 4a11d5d3af9f70241fde9e06a0b54f71a8dc7a73f03b09e082e309ea43ea3251

Available diffs

No changes file available.

Binary packages built by this source

liblexical-underscore-perl: access your caller's lexical underscore

 Starting with Perl 5.10, it is possible to create a lexical version of
 the Perl default variable $_. Certain Perl constructs like the "given"
 keyword automatically use a lexical $_ rather than the global $_.
 .
 It is occasionallly useful for a sub to be able to access its caller's
 $_ variable regardless of whether it was lexical or not. The "(_)" sub
 prototype is the official way to do so, however there are sometimes
 disadvantages to this; in particular it can only appear as the final
 required argument in a prototype, and there is no way of the sub
 differentiating between an explicitly passed argument and $_.
 .
 lexical::underscore allows you to access your caller's lexical $_
 variable as easily as:
 .
  ${lexical::underscore()}